Math, asked by vaithy4399, 1 year ago

A mother and her two sons constructed a room for ₹60000. The elder son contribute 3/8 of his mother contribution while the younger son contribute 1/2 of his mother share. How much do three contribute individually?

Answers

Answered by amitnrw
68

Answer:

Mother share = Rs 32000

Elder Son Share = Rs 12000

younger Son Contribution = Rs 16000

Step-by-step explanation:

Let Say Mother contributed = 8M  Rs

Elder Son contribution = (3/8)8M = 3M   Rs

Younger Son contribution = (1/2)8M = 4M Rs

Total Contribution = 8M + 3M + 4M = Rs 15 M

15 M = 60000

=> M = 4000

Mother share = 8M = Rs 32000

Elder Son Share = 3M = Rs 12000

younger Son Contribution = 4M = Rs 16000

Answered by shashankvky
95

Answer:

Step-by-step explanation:

Let the mother's share be 'a'

Elder son's share = (3/8)a

Younger son's share = (1/2) a

Total contribution by them = a + (3/8) a + (1/2) a

                                             = (8/8) a + (3/8) a + (4/8) a

                                             = (15/8) a

Also, total contribution = Rs 60000

Thus,

(15/8) a = 60000

a = (60000 x 8) /15

  = 4000 x 8

  = 32000

Thus

Mother's share = Rs 32000

Elder son's share  = 3/8 x 32000 = 3 x 4000 = Rs 12000

Younger son's share = 1/2 x 32000 = Rs 16000

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