Question

A mother is 20 years older than her son. Ten years ago she was 3 times as old as her son
then. Find their present ages.
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Answer 1

Answer:

$\Large{\underline{\underline{\bf{SoLuTion:-}}}}$

Answer :

Let the present age of the son be x

According to the Question,

Mother's age would be x + 20

Ten years ago,her age is 3 times her son's age

Son's age before 10 years : x - 10

Mother's age before 10 years : (x + 20) - 10

According to the Condition,

3(x - 10) = (x + 20) - 10

➠ 3x - 30 = x + 10

➠ 3x - x = 30 + 10

➠ 2x = 40

➠ x = 20

The present age of the son is 20 years

Since,

Mother's present age : x + 20 = 20 + 20 = 40 years

His mother's present age is 40 years

Answer 2

Explanation:

Let present ages of child and mother be x and x+20 respectively....

10 yrs before their ages ....child- x-10,mother- 3(x-10)....

now to make the age of mother that was 10 yrs before equal to present age i.e.3(x-10)+10 ...we can add 10 in it......the equation formed will be...

x+20=3(x-10)+10

x+20=3x-30+10

x+20=3x-20

3x-x=20+20

2x=40

x=40/2

x=20

child's present age is 20 so mother's present age will be x+20=20+20=40yrs