Math, asked by harshitaamahidar, 3 months ago

A mother is 3 times a old as her son
after 15 years, her age will be twice the
age of the son. Find their present ages​

Answers

Answered by dharshinirsvd2007
0

Answer:

45

Step-by-step explanation:

the mother's present age is 45

pls follw me

Answered by TwilightShine
22

Answer :-

  • Present age of the son = 15 years.
  • Present age of the mother = 45 years.

Given :-

  • A mother is 3 times as old as her son.
  • After 15 years, her age will be twice the age of the son.

To find :-

  • Their present ages.

Step-by-step explanation :-

  • Let the present age of the son be x.

  • His mother is 3 times as old as him, so her present age will be 3x.

After 15 years,

  • Son's age will be x + 15.
  • Mother's age will be 3x + 15.

  • It has been given that after 15 years, the mother will be twice as old as her son.

  • Twice his son's age after 15 years = 2 (x + 15)

  • Now, 3x + 15 and 2 (x + 15) must be equal.

------------------------

 \sf \implies 3x + 15 = 2 \: (x + 15)

 \sf \implies 3x + 15 = 2x + 30

  \sf\implies 3x - 2x = 30 - 15

  \sf\implies x = 15.

  • The value of x is 15.

-----------------------------------------------------------

Hence, their present ages are as follows :-

 \bf x = 15.

 \bf3x = 3 \times 15 = 45.

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