Question

A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother?

Answer 1

Let the son's age be x

Then according to the statement mother's age will be 2x

Twenty years ago ,

20 - 10 ( x - 20 ) = x

20 - 10x + 200 = x

220 = x + 10x

220 = 11x

220/11 = x

20 = x

PRESENT AGE OF SON IS 20

AND MOTHER IS 20 × 2 IS 40 YEARS OLD

Answer 2

Answer:

here is ur ans ❤❤⭐

Step-by-step explanation:

Let the son's age be x

Then according to the statement mother's age will be 2x

Twenty years ago ,

20 - 10 ( x - 20 ) = x

20 - 10x + 200 = x

220 = x + 10x

220 = 11x

220/11 = x

20 = x

PRESENT AGE OF SON IS 20

AND MOTHER IS 20 × 2 IS 40 YEARS OLD

hope it helps u(◕ᴗ◕✿)(◕ᴗ◕✿)❤❤