Question

A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother?
1) 48
2) 45
3) 42
4) 46​

Answer 1

answer:

45 years

Step-by-step explanation:

Hey there!

Here is the answer step by step.

In present,

Let son's age = X

mother's age = 2X

20 years ago,

son's age = X - 20

mother's age = 2X - 20 or 10(X - 20)

solve the equation,

2X - 20 = 10X - 200

180 = 8X

X = 180/8

Mother's present age = 2X

= 2 × 180/8

= 360/8

= 45 years

Hope it's helpful for you!