Question

a motor bike running at 5m/s pick up a velocity of 30 m/s in 5s. calculate its acceleration and distance covered​

Answer 1

Given :

▪ Initial velocity = 5mps

▪ Final velocity = 30mps

▪ Time interval = 5s

To Find :

▪ Acceleration of bike.

▪ Distance covered by bike in the given intetval of time.

Concept :

→ Acceleration is defined as the ratio of change in velocity to the time interval.

→ Since acceleration has said to be constant, we can easily apply equation of kinematics to solve this type of questions.

Calculation :

⚾ First equation of kinematics :

$\dashrightarrow\sf\:v=u+at\\ \\ \dashrightarrow\sf\:a=\dfrac{v-u}{t}\\ \\ \dashrightarrow\sf\:a=\dfrac{30-5}{5}\\ \\ \dashrightarrow\sf\:a=\dfrac{25}{5}\\ \\ \dashrightarrow\underline{\boxed{\bf{\red{a=5\:ms^{-2}}}}}$

⚾ Third equation of kinematics :

$\Rightarrow\sf\:v^2-u^2=2as\\ \\ \Rightarrow\sf\:(30)^2-(5)^2=2(5)s\\ \\ \Rightarrow\sf\:900-25=10s\\ \\ \Rightarrow\sf\:875=10s\\ \\ \Rightarrow\underline{\boxed{\bf{\orange{s=87.5\:m}}}}\:\green{\bigstar}$