A motor bike running at 5ms-1
, picks up a velocity of 30 ms-1
in 5 s. Calculate (i) acceleration (ii) distance covered
during acceleration.
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Answered by
7
Answer:
a motor bike running at 5m/s pick up a velocity of 30 m/s in 5s. calculate its acceleration and distance covered
Initial velocity, u = 5m/s
Final velocity, v = 30m/s
Time, t = 5s
Acceleration, a = v-u/t
a = 30-5/5
a = 25/5
a = m/s^2
Distance,s = ut+1/2at^2
s = 5*5 + 1/2*5(5)^2
S = 25 + 1/2*5*25
s= 87.5m
➡Acceleration = 5m/s^2
➡Distance = 87.5m
Answered by
3
Answer:
a motor bike running at 5m/s pick up a velocity of 30 m/s in 5s. calculate its acceleration and distance covered
Initial velocity, u = 5m/s
Final velocity, v = 30m/s
Time, t = 5s
Acceleration, a = v-u/t
a = 30-5/5
a = 25/5
a = m/s^2
Distance,s = ut+1/2at^2
s = 5*5 + 1/2*5(5)^2
S = 25 + 1/2*5*25
s= 87.5m
➡Acceleration = 5m/s^2
➡Distance = 87.5m
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