Question

A motor bike running at 5ms-1

, picks up a velocity of 30 ms-1

in 5 s. Calculate (i) acceleration (ii) distance covered

during acceleration.​

Answer 1

Answer:

a motor bike running at 5m/s pick up a velocity of 30 m/s in 5s. calculate its acceleration and distance covered

Initial velocity, u = 5m/s

Final velocity, v = 30m/s

Time, t = 5s

Acceleration, a = v-u/t

a = 30-5/5

a = 25/5

a = m/s^2

Distance,s = ut+1/2at^2

s = 5*5 + 1/2*5(5)^2

S = 25 + 1/2*5*25

s= 87.5m

➡Acceleration = 5m/s^2

➡Distance = 87.5m

Answer 2

Answer:

a motor bike running at 5m/s pick up a velocity of 30 m/s in 5s. calculate its acceleration and distance covered

Initial velocity, u = 5m/s

Final velocity, v = 30m/s

Time, t = 5s

Acceleration, a = v-u/t

a = 30-5/5

a = 25/5

a = m/s^2

Distance,s = ut+1/2at^2

s = 5*5 + 1/2*5(5)^2

S = 25 + 1/2*5*25

s= 87.5m

➡Acceleration = 5m/s^2

➡Distance = 87.5m