Question

A Motor boat is moving with a velocity of 108km/h and takes 4s to stop after breaks are applied calculate force exerted by breaks on motor boat with mas along with passages is 1800kg

Answer 1

a=v-u ÷t. a=acceleration
v=velocity
u=initial velocity=108km/hr
t=time
convert. mass=1800kg
F=force
108÷5/18= 40m/sec
a=v-u÷t
a=(0-40)÷4
a=40÷4
a=10

ATQ
F=MA
F=1800×10
force=18000N