Question

A motor boat starting from rest on a lake accelerates along a straight line at a constant rate of 8 mr per secHow far does the boat travel​

Answer 1

Answer:

ANSWER

Given,

Boat acceleration, a=3ms

−2

Time, t=8sec

Apply kinematic equation of motion.

s=ut+

2

1

at

2

s=0+

2

1

×3×8

2

=96m

Hence, boat travel 96m

Answer 2

Answer:

$\huge \boxed{96\ m}$

Question

A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3.0 $m/s^{2}$ for 8.0 s. How far does the boat travel during this time?

Given

$V_{i} = 0\\a^{\rightarrow} = 3.0\ m/s^2\\t = 8.0\ s\\x = ?$

Formula

$x = V_{i}t\ +\ 1/2at^2$

Solution

$x = V_{i}t\ +\ 1/2at^2\\\rm{Substitute\ the\ given\ values.}\\x = 0(8.0\ s)\ +\ \frac{1}{2}(3.0\ m/s^2)(8.0\ s)^2\\x = 0\ +\ (1.5\ m/s^{\cancel{2}})(64.0\ \cancel{s})\\\boxed{x = 96\ m}$

~Hope it helps.~

$\overbrace{\underbrace{\tt{Happy\ learning!}}}$