Question

A motor boat starting from rest on a lake accelerates in a straight line at a constant rate of 3.0m/s-2 for 8.0s. how far the boat travel during this time?

Answer 1

Hey! ! !

Solution :-

☆ Initial velocity, u = 0 (since the motor boat is initially at rest) 
Acceleration of the motorboat, a = 3 m/s2

Time taken, t = 8 s

According to the second equation of motion:

S = ut + 1/2at*2

Concept Insight - Choose the equation of motion wisely out of the three, to minimize the number of steps in calculations. Distance covered by the motorboat, s

S = 0×8 + 1/2 ×3×8×8

Hence, the boat travels a distance of 96 m.

☆ ☆ ☆ Hop its helpful ☆ ☆ ☆

☆ Regards :- ♡♡《 Nitish kr singh 》♡♡

Answer 2

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

u = 0 [starting from rest]

t = 8 sec

a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.