A motor car increases its velocity from 40 kmph to 60 kmph in 5 seconds. What will be the perimeter of acceleration of this motor car?
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Answered by
123
Answer:
Solution
u = 40km/hr = (40×5)/18 = 100/9 = 11.11 m/s
v = 60 km/hr = (60×5)/18 = 150/9 = 16.66 m/s
t = 5 sec
a = (v-u)/t = (16.66 - 11.11)/5
= 5.55/5 = 1.11 ms-2
Answered by
12
Answer:
Answer. Given : initial velocity (u) = 40 km/h, final velocity (v) = 60 km/h and time (t) = 5 sec = 5/3600 hr = 1/720 hr. Therefore, Acceleration (a) = (v-u) / t = (60-40) km/h / (1/720) hr = (20×720) km/h^2 = 14400 km/h^2. Answer : The acceleration of the car is 14400 km/h^2.
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