A motor car is going due north at a speed of 50 km/h .It makes a 90° left tern without changing the speed . The change in the velocity of the car is about
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Given, Initial Velocity v1 = 50 km/hr.
Final Velocity v2 = 50km.hr.
theta = 90 degrees
We know that Change in magnitude = (v2^2 + v1^2 - 2 v1 v2 cos 90)^1/2
= (50^2 + 50^2)^1/2
= 70.7 km/hr.
Change in velocity = 70.7 km/hr.
Hope this helps!
Final Velocity v2 = 50km.hr.
theta = 90 degrees
We know that Change in magnitude = (v2^2 + v1^2 - 2 v1 v2 cos 90)^1/2
= (50^2 + 50^2)^1/2
= 70.7 km/hr.
Change in velocity = 70.7 km/hr.
Hope this helps!
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