the perimeter of a parallelogram is 164 m. one of its side is greater than other by 30m. find length of all sides
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answer :
1st side = 26m
2nd side = 56m
3rd side = 26m
4th side = 56m
solution :
perimeter of parallelogram = 164m
let 1st side be x
therefore 2nd side will be x+30 (A/Q)
3rd side will be x ( 1st side = 3rd side )
& 4th side will be x+30 ( 2nd side = 3rd side )
perimeter of parallelogram = 2×(sum of consecutive side )
perimeter of parallelogram = 2×{x+(x+30)}
164m = 2×(x+x+30)
x+x+30 = 164/2 m = 82m
x+x = 82-30 m
2x = 52m
x = 52/2 m
x = 26m
1st side = x = 26m
2nd side = x+30 = 26+30 = 56m
3rd side = x = 26m
4th side = x+30 = 26+30 = 56m
1st side = 26m
2nd side = 56m
3rd side = 26m
4th side = 56m
solution :
perimeter of parallelogram = 164m
let 1st side be x
therefore 2nd side will be x+30 (A/Q)
3rd side will be x ( 1st side = 3rd side )
& 4th side will be x+30 ( 2nd side = 3rd side )
perimeter of parallelogram = 2×(sum of consecutive side )
perimeter of parallelogram = 2×{x+(x+30)}
164m = 2×(x+x+30)
x+x+30 = 164/2 m = 82m
x+x = 82-30 m
2x = 52m
x = 52/2 m
x = 26m
1st side = x = 26m
2nd side = x+30 = 26+30 = 56m
3rd side = x = 26m
4th side = x+30 = 26+30 = 56m
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