A motor car is moving on a circular path of radius 500 meter and has a speed 30 m/s at a particular instant. Its speed is increasing at the rate of 2 m /s²? What is its acceleration at this instant?
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Answer:
Step-by-step explanation:
Here, tangential acceleration =2m/sec^2
Radial or centripetal acceleration =V^2/r=30×30/500= 1.8 m/sec^2
So, total acceleration =( 2^2+ 1.8^2)^1/2=2.69 m/sec^2
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Answer:
Hey mate here is your answer.........
Originally Answered: A car is travelling on a circular road of radius 500m at some instant its speed is 30m/s and is increasing at the rate of 2m/s. what is its acceleration?
The acceleration has 2 components : tangential (atat= 2 m/s22) and centripetal (ar=v2r=302500=1.8ar=v2r=302500=1.8m/s22).
Net acceleration = 22+1.82−−−−−−−√22+1.82m/s22 = 2.69 m/s22.
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