Question

A motor car is moving with speed 30 ms on a circular path of radius 500 m. Its speed is increasing
at the rate of 2 m/s2? What is its acceleration at this instant?
(a) 2.5 ms
(b) 2.7 ms
(c) 2 ms?
(d) 4.5 ms?​

Answer 1

Answer:

at=v^2/r=30*30/500=1.8m/s^2

ar=2m/s^2

a=root(ar^2+at^2)

=root(7.24)

=2.7m/s^2

Answer 2

${ \huge{ \textsf{ \green{operations - - }}}}$

$at = \frac{ {v}^{2} }{r} \\ = 30 \times 30 \frac{30 \times 30}{500} \\ = 1.8m/ {s}^{2} \\ ar= 2m/s {}^{2} \\ a= \sqrt{ar {}^{2} } +at {}^{2} \\ = \sqrt{7.24} \\ = 2.7m/s {}^{2}$

Answer :

c) 2.7m/s^2