A motor car is travelling at 36 km/h. After 10 s, the velocity becomes 54 km/h. Assuming the velocity change took place at a uniform rate, find the acceleration
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u=36×1000/3600
u=10m/second
v=54×1000/3600
v=15m/second
t=10second
a=?
v=u+at
15=10+a×10
15-10=a×10
5/10=a
0.5=a
u=10m/second
v=54×1000/3600
v=15m/second
t=10second
a=?
v=u+at
15=10+a×10
15-10=a×10
5/10=a
0.5=a
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