rationalise denominator of 18/3root2-2root3
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Answer:
3(3√2 + 2√3)
Step-by-step explanation:
18/(3√2 - 2√3)
18/(3√2 - 2√3) × (3√2 + 2√3)/(3√2 + 2√3)
18(3√2 + 2√3)/(3√2 - 2√3)(3√2 + 2√3)
we know that, (a+b)(a-b) = a² - b²
Similarly, (3√2 - 2√3)(3√2 + 2√3) = (3√2)² - (2√3)² = 18 - 12 = 6
18(3√2 + 2√3)/6
= 3(3√2 + 2√3)
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