A motor car is travelling at 60 m/s on a circular road of radius 1200m
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Tangential acceleration, at=rα=4m/s2.
Radial acceleration
at=ω2r=v2r=60×601200=3m/s2.
Hence, resultant acceleration of the car
a=a21+a2r−−−−−−√=42+32−−−−−−√=5m/s2.
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Answer:
a=a21+a2r−−−−−−√=42+32−−−−−−√=5m/s2
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