Question

A motor car of mass 1000 Kg , cruising at a speed of 72 kmph, has to be brought to a stop in a straight distance of 40 m .The average force required to stop the car is

Answer 1

Answer:

The force required to stop the car will be -5000 Newton

Explanation:

f=m×a

So bye third equation of motion

V square is equals to u square + 2 a s

0=20 ×20 +2 * a*40

0=400+80×a

-400÷80=a

-5m/s square

now f = m×a

f=1000 kg × - 5

f=-5000 Newton