Obtain all pairs of consecutive odd natural number such that un each pair both are more than 10 and their sum is less than 40
Answers
Answered by
13
Linear Inequalities
Solution:
Let x be an odd natural number
The other number would be:x + 2
ATQ,
★Both the numbers are more than,
x > 10 and x + 2>10
Consider x+2>10:
x+2>10
→x>8
★Sum of the numbers is less than 40
x+(x+2)<40
»2x+2<40
»x+1<20
»x<19
Now,
The pair of numbers lie between 8 and 19
Hence,the pair of numbers would be (9,11),(11,13),(13,15) and (15,17)
Anonymous:
Great ! ♡
Answered by
14
Solution:
Let x be an odd natural number
The other number would be:x + 2
According to given question :
★Both the numbers are more than,
x > 10 and x + 2>10
Consider x+2>10:
x+2>10
→x>8
★Sum of the numbers is less than 40
x+(x+2)<40
»2x+2<40
»x+1<20
»x<19
Now,
The pair of numbers lie between 8 and 19
Hence,the pair of numbers would be (9,11),(11,13),(13,15) and (15,17)
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