A motor car of mass 1200kg is moving along a straight line with a uniform vilocity of 90km/h its vilocity is slowed down to 18km/hr in 4s by an unbalanced external force.Calculate the acceleration change in momentum force.
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apply 1st eqn of motion
18=90+a*4
therefore a=-72/4= -18kmph
18=90+a*4
therefore a=-72/4= -18kmph
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