A motor car of mass 25kg is moving with a certain velocity. It is brought to rest by the application of brakes, within a distance of 20m when average resistance being offered to it is 500n .What is the velocity of motor car?
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Given,
Mass of the motor car=25kg
Final velocity(v) =0
Initial velocity =?
Acceleration =F/m= - 500/25=20 m/s^2
We have v^2-u^2=2as
u^2=v^2-2as
u^2=0-2(20).20
u^2=0-800
u^2=-800
u= root of ( - 800)
Hope it helped u!
Mass of the motor car=25kg
Final velocity(v) =0
Initial velocity =?
Acceleration =F/m= - 500/25=20 m/s^2
We have v^2-u^2=2as
u^2=v^2-2as
u^2=0-2(20).20
u^2=0-800
u^2=-800
u= root of ( - 800)
Hope it helped u!
Amrudha123456:
Sorry 200kg
so jst interchange the value of mass from 25 to 20kg
200kg*
u will get the ans.
will u be able to do?
And that I got when I interchange is -10 m/s
what did u ger in Acceleration?
I mean ans is -10 m/s
u have the ans
bec i also have to calculate na
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Refer to the attachment, hope it helps..
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