A motor car starting from rest,moves with uniform acceleration and attains a velocity of 10 m/s in 5 so. It then moves with uniform velocity and finally brought to rest in 25 my Under uniform retardation. The total distance covered by the car is 225m. The retardation of the car is.................m/s2.
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It then moves with uniform velocity and finally bought to rest in 32m under uniform retardation. The total distance Covered by the car is 464m. Draw velocity-time graph and calculate time total ... Ankur , Meritnation Expert added an answer, on 29/5/15. Kindly refer to the link ... Live Courses. IIT JEE · AIPMT · CBSE Class 6-10
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