Question

A motor cycle and rider having a total weight
W=1500N travels in a vertical plane following a
curve of radius r=50m at a speed of 10m/sec.
Compute the thrust exerted by the road as it
passes over the crest C on the curve as shown
in the Fig. Assume g=10m/s2
ans.
1600N
1500N
1000N
1200N​

Answer 1

In cases like these, the thrust (or normal) exerted by the road is the sum or difference of the weight of the body and centripetal force.

In this case,. thrust = weight - centripetal force

= mg - m v^2 / r

= 1500 - (1500/10) × ( 10^2 ) / 50

= 1500 - 150 × 100 / 50

= 1500 - 300

= 1200 N

PS- The figure is not given and the question isn't as clear, but this is what I think the question is asking. Do tell me if I'm wrong.