Physics, asked by Pabhijith8410, 10 months ago

A motor cycle is moving along a straight horizontal road
with a speed v₀. If the coefficient of friction between the
tyres and the road is μ, the shortest distance in which the
car can be stopped is
(a)v₀²/2μg (b)v²/μ
(c)(v₀/μg)² (d) v₀/μg

Answers

Answered by kjha95830

0

Answer:

(a)

Explanation:

v^2=u^2+2as
0-Vo^2=2(ug)s
therefore,

s=Vo^2/2ug

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