A motor cycle moving with a speed of 5 m/s is subjected to an acceleration of 0.2 m/s.calculate the speed of motorcycle after 10 sec and the distance traveled in this time
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Answered by
2
d=5×10+0.5×0.2×100
=50+10
=60m
and v=5+0.2×10
=5+2
=7m/s
=50+10
=60m
and v=5+0.2×10
=5+2
=7m/s
Answered by
2
1) Finding the speed after 10s:
v=u+at
v=5+0.2*10
v=7m/s
2) distance:
s=ut+1/2 at^2
s=5*10+1/2* 0.2*10*10
s=50+1/2*20
s=50+10
s=60m
v=u+at
v=5+0.2*10
v=7m/s
2) distance:
s=ut+1/2 at^2
s=5*10+1/2* 0.2*10*10
s=50+1/2*20
s=50+10
s=60m
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