Question

A motor cycle starts to move from rest and covers 200m distance in 6 seconds. Calculate the final velocity and acceleration of the motor cycle.

Answer 1

Answer:

here is your answer

Explanation:

Answer 2

Answer:

final velocity=66.6m/s

accelaration=11.1m/s^2

Explanation:

Given:                  

u=0m/s

s=200m

t=6s

By 2 law of motin

=> s=ut+1/2at^2

=> 200=0(6)+1/2a(6)^2

=>200=1/2a(36)

=>200=18a

=>a=200/18

=11.1m/s^2

Thus,

=>v=u+at

=>v=0+11.1(6)

=>v=66.6m/s

Hope this help....