A motor cycle starts to move from rest and covers 200m distance in 6 seconds. Calculate the final velocity and acceleration of the motor cycle.
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Answer:
here is your answer
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Answer:
final velocity=66.6m/s
accelaration=11.1m/s^2
Explanation:
Given:
u=0m/s
s=200m
t=6s
By 2 law of motin
=> s=ut+1/2at^2
=> 200=0(6)+1/2a(6)^2
=>200=1/2a(36)
=>200=18a
=>a=200/18
=11.1m/s^2
Thus,
=>v=u+at
=>v=0+11.1(6)
=>v=66.6m/s
Hope this help....
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