A motor cyclist drives from A to B with a uniform speed of 30km/h and returns back with a speed of 20km/h. Find its average speed
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Hi friend,
# 24 km/hr
_____________________________
➡Solution :-
Let , the distance between A and B is D
Then , Time taken by the driver with uniform speed at 30km/h
➡T1 = Distance / speed = D/30km/h
➡In same way , when he returns with an uniform speed at 20km/h . Then ,
T2 = D/20km/h
■Avg. Speed = Total Distance/Total time taken
➡Therefore ,
=> ( D+D)/(D/30 + D/20) km/h
Or , 2 ×30×20 / (30+20) km/h
Or, 24km/h ( proved)...i hope it helps you
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# 24 km/hr
_____________________________
➡Solution :-
Let , the distance between A and B is D
Then , Time taken by the driver with uniform speed at 30km/h
➡T1 = Distance / speed = D/30km/h
➡In same way , when he returns with an uniform speed at 20km/h . Then ,
T2 = D/20km/h
■Avg. Speed = Total Distance/Total time taken
➡Therefore ,
=> ( D+D)/(D/30 + D/20) km/h
Or , 2 ×30×20 / (30+20) km/h
Or, 24km/h ( proved)...i hope it helps you
___________________________
Mark me as a brainliest ✌.
Be brainly !
snehad2906:
Thanks a lot!! U really helped
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