Physics, asked by latikapratt277, 1 month ago

A motor has a useful power output of 3 kW, what can it do it one second?

Answers

Answered by OoINTROVERToO

0

Power = Work Done / Time

Work Done = Power × Time

Work Done = 3 kW × 1 sec

Work Done = 3 × 10³ W × 1 sec

Work Done = 3 × 10³ J

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