Question

A motor of power 0.98 kW drags a mass 100kg through 4m on a surface having co efficient of friction 0.3 .Time of that mass is, the answer is 1.2 secs but can someone pls show the steps​

Answer 1

Power =force * displacement / time

given

P=0.98 kW

m=100 kg

s=4

mu= 0.3

( from s=at sqr)

F=mu ma (a = s/t sqr)

0.3*100*4/t sqr

120/t sqr

power =force * displacement / time

0.98 kW = 120/t sqr * 4/t

Solve it you will get the answer.

Please mark as brainiest

Answer 2

Answer:

hi dear

yes all Gud

what's about you?

how was your studies

Explanation:

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saranghae!