Question

a motorbike accelerates from 54km/hr to 72km/hr in 2 seconds. calculate acceleration and distance covered by the motorbike​

Answer 1

u = 54 kmph

v = 72kmph

t = 2 secs

a = v-u/t = 72 - 54/2 = 9 ms^-2

s = ut + 1/2at^2

  = (54 x 2) + (1/2 x 9 x 2^2)

  = 108 + 18

  = 126 km

Answer 2

Answer:

a = 2.5 m/s^2 and d = 35 m

Step-by-step explanation:

acceleration = change in V by time

V1 = 54 km / hr = 15 m/s

V2 = 72 km/hr = 20 m/s

a = delta V / t

a = 20-15/ 2

a = 2.5 m/s^2

now for distance

2ad = V2^2 - V1^2

2(2.5)d = (20)^2 - (15)^2

5d = 175

d = 175/5

d = 35 m