A motorbike initially moving at 18 km/h accelerates at a rate of 5 m/s for 5s calculate the distace covered by it from start
Answers
Answered by
17
hey your answer is.......☺️
___________;;;_;;;;;;;__________
initial velocity = 18km/h = 18 × 5/18 = 5m/s
acceleration = 5m/s^2
time = 5s
distance (s) = ut + 1/2at^2
= 5×5 + 1/2 × 5 × 5^2
= 25 + 125/2 = 50+125÷2 = 175/2 =
=87.5m
hope it helps...................^_^
___________;;;_;;;;;;;__________
initial velocity = 18km/h = 18 × 5/18 = 5m/s
acceleration = 5m/s^2
time = 5s
distance (s) = ut + 1/2at^2
= 5×5 + 1/2 × 5 × 5^2
= 25 + 125/2 = 50+125÷2 = 175/2 =
=87.5m
hope it helps...................^_^
Answered by
0
sdwfegrthgrfedqffbfgbrhgyhfn
Similar questions