Physics, asked by tanmayjana9117, 1 year ago

A motorbike initially moving at 18 km/h accelerates at a rate of 5 m/s for 5s calculate the distace covered by it from start

Answers

Answered by vamsibat10
17
hey your answer is.......☺️
___________;;;_;;;;;;;__________
initial velocity = 18km/h = 18 × 5/18 = 5m/s
acceleration = 5m/s^2
time = 5s
distance (s) = ut + 1/2at^2
= 5×5 + 1/2 × 5 × 5^2
= 25 + 125/2 = 50+125÷2 = 175/2 =
=87.5m

hope it helps...................^_^
Answered by singhprince0457
0

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