A racing car has an acceleration of 4m/s┬▓,what distance will it cover in 20 second after start .
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Answered by
4
hey here is your answer..........☺️
initial velocity (u)= 0
acceleration (a) = 4m/s^2
time = 20s. then
distance (s) = ut + 1/2 at^2
= 1/2 × 4 × (20)^2
= 2 ×400 = 800m.
hope it helps.......
initial velocity (u)= 0
acceleration (a) = 4m/s^2
time = 20s. then
distance (s) = ut + 1/2 at^2
= 1/2 × 4 × (20)^2
= 2 ×400 = 800m.
hope it helps.......
Answered by
0
Refer https://brainly.in/question/4391450
Take t = 20 instead of 10. You get the answer 800 m.
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