A motorbike is moving with velocity of 2.5 m/s. It is accelerated at a rate of 2 m/s square for 12 seconds. Find the final velocity of the motorbike.
Answers
Answered by
1
we know that
(v-u)/t=(v-2.5)/12=2
=v=26.5
(v-u)/t=(v-2.5)/12=2
=v=26.5
Answered by
1
v=u+at
v = ?
u = 2.5m/s
a = 2m/s²
t = 12 sec
v = 2.5 + 2 X 12
=> 2.5 + 24
=> 26.5m/s
therefore final velocity = 26.5m/s
v = ?
u = 2.5m/s
a = 2m/s²
t = 12 sec
v = 2.5 + 2 X 12
=> 2.5 + 24
=> 26.5m/s
therefore final velocity = 26.5m/s
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