Question

A motorbike of mass 100 kg moving at a velocity of 60km/h is stopped in 10 seconds. Find the magnitude of force applied.​

Answer 1

Answer:

-167 N

Explanation:

60km/h=16.667m/s

a=v-u/t

=0-16.667/10

= -16.7/10(estimating 16.667=16.7)

=-1.67m/s^2

we know,

f = ma

= ( 100 x -1.67 ) kg m/ s^2

= -167 N

Answer 2

Explanation:

Mass(m) = 100 kg

initial velocity(u) = 60 km/h

Final velocity (v) = 0

Time = 10 s

Force(f) = ?

Change into m/s

initial velocity = 60*5/18

initial velocity = 16.66........

F = m(v-u/t)

F = 100(0-16.666..../10)

F = 100*-16.666..../10

F = -166.66.......