A motorboat is moving towards north with a speed of 10 m s-1 and water in the river is flowing with a speed of 5 msl in the direction of 60° east of south. Calculate the resultant velocity of the motor boat.
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Answer:
Given,
velocity of the water current v
c
=10 km/s
velocity of the motorboat v
b
=25km/h
angle between north and south east is 120
o
Resultant velocity v
R
=
v
b
2
+v
c
2
+2v
b
v
c
cos120
∘
(25)
2
+(10)
2
+2(25)(10)(
2
−1
)
=22km/h
−1
The resultant velocity of the boat is 22km/h
−1
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