A motorboat is racing towards north at 20km/h and water current in that region is 10km/h in a direction 60^(@) east of south.The resultant velocity of boat is
Answers
Given : A motorboat is racing towards north at 20km/h
water current in that region is 10km/h in a direction 60° east of south.
To Find : The resultant velocity of boat
Solution:
A motorboat is racing towards north at 20km/h
=> Velocity toward north = 20 km/hr
water current in that region is 10km/h in a direction 60° east of south.
=> Velocity water current in South = 10 Cos 60° = 10 (1/2) = 5 km /hr
= - 5 km/hr in North
Hence resultant in North = 20 - 5 = 15 km/hr
Velocity water current in East = 10Sin 60° = 10 ( √3 /2 ) = 5√3 km /hr
North Component = 15 km/hr
East Component = 5√3 km/hr
Velocity magnitude = √15² + (5√3)²
= 5 √ (9 + 3)
= 5 √12
= 10√3
= 17.3 km/hr
The resultant velocity of boat is 17.3 km/hr
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