Question

A motorboat starting from
from_nest on a lake
accelerates in a
straight line at a constart
of 3ms-2
for 8s How far does the
travel during this
rate of
this time?
boat​

Answer 1

Answer:

a = 3m/s^2

t= 8s

d = ?

given : the boat is starting from rest so....u = 0

using s = ut + 1/2 at^2

s= 0 × t + 1/2 × 3 × 8

s= 0 + 12

=> s = 12 m

Explanation:

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Answer 2

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

u = 0 [starting from rest]

t = 8 sec

a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.