ANSWER above question plz with explinetion on book
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rathodparshram:
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Answer:
In ∆ PQR
QR= 12
SR= 4
QS+SR= QR. (Q-S-R)
QS+ 4= 12
QS= 12-4
QS= 8
1. A(∆PSR)/A(∆PQR)= SR/QR. triangles with equal height
= 4/12
= 1/3
2. A(∆ PQS)/A(∆ PQR) = QS/QR. triangles with equal height
= 8/12
= 2/3
3. A(∆PQS)/A(∆PSR) = QS/ SR. triangles with common height
= 8/4
= 2
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