Question

A motorboat starting from rest on a lake
accelerates in straight line at a constant
rate of 3.0 m/sec square for 8.0s. Howfar
does the boat travel during this time?​

Answer 1

Answer:

Given initial velocity =0

Acceleration =3m/s^2

Time=8 second

Distance =S=ut +1/2at^2

0×8+1/2×3×(8)^2

0+1/2×3×64

0+1×3×32=96

Answer=96metre

Answer 2

Answer:-

The boat travels 96 m during this time.

$\rule{200}{1}$

Explanation:-

Given:-

• Acceleration (a) = 3 m/s²
• Time (t) = 8 seconds.

To find:-

• Distance travelled by boat = ?

Solution:-

As here,the bost starts from rest,so it's initial velocity will be 0.

We know equation of motion:-

$\star\:{\boxed{\rm{\red{s = ut + \dfrac{1}{2}\: at^2 }}}}$

Here, a = acceleration,s = distance travelled, u = initial velocity & t = time.

Here,putting all values:-

→ s = 0 × 8 + ½ (3 × 8²)

→ s = 0 + ½ (3 × 64)

→ s = ½ (192)

→ s = 192/2

→ s = 96 m

Therefore,

Distance travelled by boat = 96 m

$\rule{200}{1}$

More formulas related to it:-

• v = u + at

• v² = u² + 2as

• a = (v - u)/t