Physics, asked by vikasa93, 11 months ago

a motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3ms*-2 for 8s. how far does the boat travel during this time​

Answers

Answered by Anonymous
6

Answer:

Using equation of motion and neglecting the effect of the streams we have,

S= ut+1/2at^2

S = 1/2 *3*8^2

S = 96m

Answered by Anonymous
0

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

 \\  \star \: {\boxed{\sf{\purple{s = ut +  \dfrac{1}{2}a {t}^{2}  }}}} \\

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

u = 0 [starting from rest]

t = 8 sec

a = 8 m/s²

Substituting the values in the equation ,

 \\   : \implies \sf \: s = (0)(8) +  \dfrac{1}{2} (3 )  {(8)}^{2}   \\  \\

 \\   : \implies \sf \: s =  \dfrac{1}{2} (3)(64) \\  \\

 \\   : \implies \sf \: s = 32 \times 3 \: m \\  \\

 \\   : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \:  \bigstar \\  \\

Hence ,

The distance travelled by the boat during that time is 96 m.

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