Question

what is the de brogli wavelength of an electron in bohrs obit of radius 0.51 A in hydrogen atom​

Answer 1

Explanation:

DeBroglie Wavelength

A convenient form for the DeBroglie wavelength expression is

where hc = 1239.84 eV nm and pc is

expressed in electron volts.

This is particularly appropriate for comparison with photon wavelengths since for the photon, pc=E and a 1 eV photon is seen immediately to have a wavelength of 1240 nm. For massive particles with kinetic energy KE which is much less than their rest mass energies:

Answer 2

Answer:3280 nM or 3.28 A

Explanation:

Use r = n^2 × 0.53A

n = 1(approx)

Then use,

2πr = n× wavelength

Wavelength = 2π×0.51 /1

= 3280 nm