Question

A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3 ms

–2 for 8 s. How far

does the boat travel during this time?​

Answer 1

Answer:

equation of kinematics: motion :

        s = u t + 1/2 a t²

  here u = 0 m/sec  a = 3.0 m/sec/sec    t = 8.0 sec

          s  = 0 * 8.0 + 1/2 * 3 m/sec² * (8.0 sec)²

     distance travelled in 8 sec = 96 meters

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Explanation:

Answer 2

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

u = 0 [starting from rest]

t = 8 sec

a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.