Question

A motorboat starting from rest on a lake accelerates in a straight

line at a constant rate of 5 m/s2 for 10 secs. How far does the boat

travel during this time?

its urgent!!

Answer 1

Answer:

250m

Explanation:

s=ut +1/2at2 ,.s=o + 1/2×5×100; s=250m

Answer 2

$\large \dag$ Question :-

A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 5 m/s² for 10 secs. How far does the boat travel during this time?

$\large \dag$ Answer :-

$\large\dashrightarrow\underline{{\underline{\frak{{Distance \: \text Traveled =\pmb{ 250 \: m} }}}}}$

$\large \dag$ Step by step Explanation :-

Here we have :

• Initial Velocity = u = 0 m/s

• Acceleration = a = 5 m/s²

• Time = t = 10 s

❒ We Have 2nd Equation of Motion as :

$\large \bf \red \bigstar \: \: \orange{ \underbrace{ \underline{s=ut+\dfrac{1}{2}at^2}}}$

⏩ Applying 2nd Equation of Motion :

$:\longmapsto \rm s = 0 \times 10 + \frac{1}{2} \times 5 \times {10}^{2}$

$:\longmapsto \rm 0 + \frac{1}{2} \times 5 \times 100$

$\purple{ \large :\longmapsto  \underline {\boxed{{\bf s = 250 \: m} }}}$

Therefore,

$\large\underline{\pink{\underline{\frak{\pmb{Distance \: \text Traveled = 250 \: m }}}}}$

$\large \dag$ Additonal Information :-

$\Large \red \bigstar$Three Equations of Motion :

$\large \qquad \boxed{\boxed{\begin{array}{cc} \maltese \: \: \bf v = u + at \\ \\ \maltese \: \: \bf s = ut + \dfrac{1}{2}a {t}^{2} \\ \\ \maltese \: \: \bf{v}^{2} - {u}^{2} = 2as\end{array}}}$