A motorboat starting from rest on lake accelerates in a straight line at a constant rate of 3m/s square for 8sec. How far does the boat travel during this time?
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Answered by
3
here....
u =0
t=8s
a=3m/s sq
s=?
we know,
s=ut +1/2×at sq
s=0×8+1/2×3×8×8
s =1/2×3×64
s=96m....
It will help u..sure
u =0
t=8s
a=3m/s sq
s=?
we know,
s=ut +1/2×at sq
s=0×8+1/2×3×8×8
s =1/2×3×64
s=96m....
It will help u..sure
henri:
oh no itzz 192 m...sorry frnd..itzz 192m
Frnd plz show the solution
Dear frnf Henri......It's 96m.....I've shown the calculation by third equation of motion.....you would have done through some other complicated or wrong way....
yeah...i thnk so..
well Henri...where do u belong from???
m frm india..u
me too
aww
state??
plzz mark it as brainliest
Answered by
0
u = 0
a = 3 m/sec square
t = 8 sec
According to third formulae of motion
s =ut + 1/2 a t square
- Here u = initial speed
-a = accleration
-t = time
- s = distance travelled
s = 0 x 8 + 1/2 x 3 x 8 x 8
s = 3 x 4 x 8
s = 96 m...
it tarvels 96m
formulaes of motion are-
1. v=u+at
2. v square = u square + 2as
3. s = ut + 1/2 a t square
a = 3 m/sec square
t = 8 sec
According to third formulae of motion
s =ut + 1/2 a t square
- Here u = initial speed
-a = accleration
-t = time
- s = distance travelled
s = 0 x 8 + 1/2 x 3 x 8 x 8
s = 3 x 4 x 8
s = 96 m...
it tarvels 96m
formulaes of motion are-
1. v=u+at
2. v square = u square + 2as
3. s = ut + 1/2 a t square
if u are thinking tojust copy...dont copy these lines 6,7,8,9 and 14,15,16,17
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