Question

a motorboat starts from rest and moves with uniform acceleration. if it attains the velocity of 15 m/s in 5 s calculate the acceleration and the distance travelled in that time ​

Answer 1

Answer:

Here is the answer

Initial velocity = 0

final velocity = 15 m/s

time = 5s

To find acceleration

a = v - u / t

1. 15 -0 /5
2. 15 /5

3 . 3

answer is 3m /s^2

s = ut +1/2 at ^2

s = 0×5 +1/2 ×3 ×5×5

s = 0+1/2 ×75

s= 37.5

distance travelled is 37. 5m

Answer 2

Answer:

Acceleration = 3 m/s²

Distance = 37.5 m

Explanation:

u = 0 m/s

v = 15 m/s

t = 5 s

a = (v - u)/t

=> a = (15 - 0)/5

=> a = 15/5

=> a = 3 m/s²

s = ut + ½ at²

=> s = 0 * 5 + ½ * 3 * 5²

=> s = 0 + ½ * 3 * 25

=> s = 75 / 2

=> s = 37.5 m

So,

Acceleration = 3 m/s²

Distance = 37.5 m