a motorboat whose speed is 18 km per hour is still in water takes 1 hour more to go 24 km upstream than to return downstream to the same spot .find the the speed of the stream
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Given, speed of the boat in still water = 18 km/hr.
Let the speed of the stream be x km/hr.
Speed of the boat upstream = Speed of boat in still water – Speed of the stream
∴ Speed of the boat upstream = ( 18 – x ) km/hr
Speed of the boat downstream = Speed of boat in still water + Speed of the stream
∴ Speed of the boat downstream = ( 18 + x ) km/hr
Time of upstream journey = Time for downstream journey + 1 hr
*The image will be the answer in this part..
⇒ 48x = 324 – x2
⇒ x2 + 48x – 324 = 0
=>x²+54x-6x-324=0
=>x(x+54)-6(x+54)=0
=>(x-6)(x+54)=0
=>Either, || Or,
x=6, x=-54(The negative value is ignored)
∴ x = 6 (Speed of the stream cannot be negative)
Thus, the speed of stream is 6 km/hr.
Let the speed of the stream be x km/hr.
Speed of the boat upstream = Speed of boat in still water – Speed of the stream
∴ Speed of the boat upstream = ( 18 – x ) km/hr
Speed of the boat downstream = Speed of boat in still water + Speed of the stream
∴ Speed of the boat downstream = ( 18 + x ) km/hr
Time of upstream journey = Time for downstream journey + 1 hr
*The image will be the answer in this part..
⇒ 48x = 324 – x2
⇒ x2 + 48x – 324 = 0
=>x²+54x-6x-324=0
=>x(x+54)-6(x+54)=0
=>(x-6)(x+54)=0
=>Either, || Or,
x=6, x=-54(The negative value is ignored)
∴ x = 6 (Speed of the stream cannot be negative)
Thus, the speed of stream is 6 km/hr.
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manraaditya155:
thx
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Answer:
Let the speed of stream be x km / hr
For upstream = ( 18 - x ) km / hr
For downstream = ( 18 + x ) km / hr
A.T.Q.
24 / 18 - x - 24 / 18 + x = 1
48 x = 324 - x²
x² + 48 x - 324 = 0
( x + 54 ) ( x - 6 ) = 0
x = - 54 or x = 6
Since speed can't be negative .
Therefore , speed of the stream is 6 km / hr .
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