A motorboat whose speed is 20 km per hour in still water takes 1 hour more to go 48
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Let, the speed of the stream be x km/hr
Speed of boat in still water =20 km/hr
∴Speed of boat with downstream 20+x km/hr
∴ Speed of boat with upstream 20−x km/hr
As per given condition
20−x48−20+x48=1
⟹48[20−x1−20+x1]=1
⟹[(20−x)(20+x)20+x−20+x]=481
⟹400−x22x=481
⟹96x=400−x2
⟹x2+96x−400=0
⟹x2+100x−4x−400
⟹x(x+100)−4(x+100)=0
⟹(x−4)(x+100)=0
Either, x=4 or x=−100
∵ Speed cannot be negative ∴x=4 km/hr is considered.
∴ the speed of the stream =4 km/hr
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