A motorcycle comes to rest by an acceleration of 10m/s2 in 3 minutes. Calculate its initial velocity.
Answers
Answer:
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Given :
- A motorcycle comes to rest by an acceleration of 10m/s² in 3 minutes.
To Find :
- Initial Velocity (u) = ?
Solution :
To answer any question to do with mass, acceleration, velocity ,etc. you can use one or more of this set of equations. They are called the 'kinematic' equations and They are really easy to re-arrange, when you need to find the 'unknown quantity', that the question is asking for. Below these equations I will show you the general problem solving strategy to solve these quickly and easily.
The Kinematic Equations :
- v = u + at
- s = ut + ½ at²
- v² - u² = 2as
- Sₙₜₕ = u + a/2 (2n - 1)
Here,
- Final Velocity (v) = 0 m/s
- Time (t) = 3 minutes
- Initial Velocity (u) = ?
- Acceleration (a) = 10 m/s²
First of all convert the time from minutes to seconds :
→ Time taken = 3 minutes
→ Time taken = 3 × 60
→ Time taken = 180 seconds
- Hence,the time taken by the motorcycle is 180 seconds.
Now, let's calculate the initial velocity by using first equation of motion :
→ v = u + at
→ 0 = u + (-10) × 180
→ 0 - u = -1800
→ -u = -1800
→ u = 1800 m/s
- Hence,the initial velocity of the motorcycle is 1800 m/s .