Question

A motorcycle is being driven at a speed of 20 m per second when brakes are applied to bring it to rest in 5 seconds find the the deceleration produced

Answer 1

In this case,

u (Initial Velocity) = 20 m/sec
v (final velocity) = 0 m/sec (at rest)
time (t) = 5 secs

a = (v-u) /t
a= (0 - 20) / 5

a= -20 / 5

a = -4 m/sec square

Therefore Deceleration produced is 4 m/sec square

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Answer 2

Given: Initial speed, $u=20\text{ m/s}$

To find: deceleration

A motor cycle is being driven at a speed of 20 m/s when brake are applied to bring it to rest in 5 seconds.

Using equation formula,

$v=u+at$

where, v is final velocity, u is initial velocity and t is time.

After rest final speed of motorcycle is 0

$0=20+a\times 5$

$a=-\dfrac{20}{5}$

$a=-4\text{ m/s}^2$

Hence, the deceleration of motorcycle is 4 m/s².